I found a subnetting practice site and was doing 'ok' -- until this question:
What is the last valid host on the subnetwork 192.168.149.0 255.255.255.224?
224 means increments of 32, correct? So that would be 0, 32, 64, 96,,128, 160 so the last valid address would be 192.168.159.30, correct?
But the answer given is 192.168.149.30.
Maybe a typo and they meant 192.168.159.30?
Otherwise, can you please explain where I am going wrong on this one?
OK, I see my error. The 0. 32, 64, . . . increments are in the fourth octet, So the subnet is 192.168.149.0 and addresses 192.168.149.1 - 30; next subnet is 192.168.149.32 and addresses 192.168.149.33 - 62 . . . and so on. . . .
David,
Great job in figuring it out! That's the kind of troubleshooting that will get you ready for the exam!
Cordially,
Ronnie Wong
Host, ITProTV
Cordially,
Ronnie Wong
Edutainer Manager, ITProTV
*if the post above has answered the question, please mark as solved.
**All "answers" and responses are offered "as is" and my opinion. There is no implied service, support, or guarantee by ITProTV.
