• J
    Jason Leschnik

    if we just count bits from the original class B numbers (128-191) to the first 16 bits that's 13 bits after the 1st 3 bits 2^13= 8192 possible...

    Aren't there 16384 possible Class B Networks? You've got 16-bits in the native Class B mask and 2 of those bits '10' (10000000-10111111) [128-191]) are fixed, leaving 2^14 bits for addressing?

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